blender/intern/iksolver/extern/IK_solver.h
Kent Mein f78de74b20 WooHoo me again ;)
I took out the following from the includes in the intern dir that still had
it:
-#ifdef HAVE_CONFIG_H
-#include <config.h>
-#endif

Kent
--
mein@cs.umn.edu
2002-12-26 18:25:17 +00:00

206 lines
7.1 KiB
C

/**
* $Id$
* ***** BEGIN GPL/BL DUAL LICENSE BLOCK *****
*
* This program is free software; you can redistribute it and/or
* modify it under the terms of the GNU General Public License
* as published by the Free Software Foundation; either version 2
* of the License, or (at your option) any later version. The Blender
* Foundation also sells licenses for use in proprietary software under
* the Blender License. See http://www.blender.org/BL/ for information
* about this.
*
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with this program; if not, write to the Free Software Foundation,
* Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
*
* The Original Code is Copyright (C) 2001-2002 by NaN Holding BV.
* All rights reserved.
*
* The Original Code is: all of this file.
*
* Contributor(s): none yet.
*
* ***** END GPL/BL DUAL LICENSE BLOCK *****
*/
/**
* $Id$
* Copyright (C) 2001 NaN Technologies B.V.
*
* @author Laurence
* @mainpage IK - Blender inverse kinematics module.
*
* @section about About the IK module
*
* This module allows you to create segments and form them into
* chains. You can then define a goal point that the end of the
* chain should attempt to reach - an inverse kinematic problem.
* This module will then modify the segments in the chain in
* order to get the end of the chain as near as possible to the
* goal. This solver uses an inverse jacobian method to find
* a solution.
*
* @section issues Known issues with this IK solver.
*
* - The current solver works with only one type of segment. These
* segments always have 3 degress of freedom (DOF). i.e. the solver
* uses all these degrees to solve the IK problem. It would be
* nice to allow the user to specify different segment types such
* as 1 DOF joints in a given plane. 2 DOF joints about given axis.
* - There is currently no support for joint constraints in the
* solver. This is within the realms of possibility - please ask
* if this functionality is required.
* - The solver is slow, inverse jacobian methods in general give
* 'smooth' solutions and the method is also very flexible, it
* does not rely on specific angle parameterization and can be
* extended to deal with different joint types and joint
* constraints. However it is not suitable for real time use.
* Other algorithms exist which are more suitable for real-time
* applications, please ask if this functionality is required.
*
* @section dependencies Dependencies
*
* This module only depends on Moto.
*/
#ifndef NAN_INCLUDED_IK_solver_h
#define NAN_INCLUDED_IK_solver_h
#ifdef __cplusplus
extern "C" {
#endif
/**
* External segment structure
*/
/**
* This structure defines a single segment of an IK chain.
* - Individual segments are always defined in local coordinates.
* - The segment is assumed to be oriented in the local
* y-direction.
* - seg_start is the start of the segment relative to the end
* of the parent segment.
* - basis is a column major matrix defining the rest position
* of the bone.
* - length is the simply the length of the bone.
* - basis_change is a 3x3 matrix representing the change
* from the rest position of the segment to the solved position.
* In fact it is the transpose of this matrix because blender
* does something weird with quaternion conversion. This is
* strictly an ouput variable for returning the results of an
* an ik solve back to you.
* The local transformation specified as a column major matrix
* of a segment is then defined as.
* translate(seg_start)*basis*transpose(basis_change)*translate(0,length,0)
*/
typedef struct IK_Segment_Extern {
float seg_start[3];
float basis[9];
float length;
float basis_change[9];
} IK_Segment_Extern;
typedef IK_Segment_Extern* IK_Segment_ExternPtr;
/**
* External chain structure.
* This structure is filled when you call IK_LoadChain.
* The first segment in the chain is the root segment.
* The end of the last segment is the end-effector of the chain
* this is the point that tries to move to the goal in the ik
* solver.
* - num_segments is the number of segments in the array pointed
* to by the member segments.
* - chain_dof is the number of degrees of freedom of the chain
* that is the number of independent ways the chain can be changed
* to reach the goal.
* - segments points to an array of IK_Segment_Extern structs
* containing the segments of this chain.
* - intern is pointer used by the module to store information
* about the chain. Please do not touch the member in any way.
*/
typedef struct IK_Chain_Extern {
int num_segments;
int chain_dof;
IK_Segment_ExternPtr segments;
void * intern;
} IK_Chain_Extern;
typedef IK_Chain_Extern* IK_Chain_ExternPtr;
/**
* Create a clean chain structure.
* @return A IK_Chain_Extern structure allocated on the heap.
* Do not attempt to delete or free this memory yourself please
* use the FreeChain(...) function for this.
*/
extern IK_Chain_ExternPtr IK_CreateChain(void);
/**
* Copy segment information into the chain structure.
* @param chain A chain to load the segments into.
* @param segments a ptr to an array of IK_Input_Segment_Extern structures
* @param num_segs the number of segments to load into the chain
* @return 1 if the chain was correctly loaded into the structure.
* @return 0 if an error occured loading the chain. This will normally
* occur when there is not enough memory to allocate internal chain data.
* In this case you should not use the chain structure and should call
* IK_FreeChain to free the memory associated with the chain.
*/
extern int IK_LoadChain(IK_Chain_ExternPtr chain,IK_Segment_ExternPtr segments, int num_segs);
/**
* Compute the solution of an inverse kinematic problem.
* @param chain a ptr to an IK_Segment_Extern loaded with the segments
* to solve for.
* @param goal the goal of the IK problem
* @param tolerance .The distance to the solution within which the chain is deemed
* to be solved.
* @param max_iterations. The maximum number of iterations to use in solving the
* problem.
* @param max_angle_change. The maximum allowed angular change. 0.1 is a good value here.
* @param output. Results of the solution are written to the segments pointed to by output.
* Only the basis and basis_change fields are written. You must make sure that you have
* allocated enough room for the output segments.
* @return 0 if the solved chain did not reach the goal. This occurs when the
* goal was unreachable by the chain end effector.
* @return 1 if the chain reached the goal.
*/
extern int IK_SolveChain(
IK_Chain_ExternPtr chain,
float goal[3],
float tolerance,
int max_iterations,
float max_angle_change,
IK_Segment_ExternPtr output
);
/**
* Free a chain and all it's internal memory.
*/
extern void IK_FreeChain(IK_Chain_ExternPtr);
#ifdef __cplusplus
}
#endif
#endif // NAN_INCLUDED_IK_solver_h